Respuesta :
Answer:
A. 13.3% (1d.p)
B.
Explanation:
A. Efficiency can be calculated by dividing useful output by total input and multiply it by 100.
Therefore (10000/75000)x100= 13.333333..%
B. Most of the energy is lost as heat energy.
A. (10000/75000)100%
=13.3%, cor to 3sf
B.prob used to warm up the engine/ lost to atmosphere
=13.3%, cor to 3sf
B.prob used to warm up the engine/ lost to atmosphere