Answer:
Step-by-step explanation:
slope of line through A ,B is
m=(-2-6)/(5-2)=-8/3
slope of line perpendicular to AB Is 3/8
mid-point of AB =((2+5)/2,(6-2)/2)=(7/2,2)
eq. of reqd line is
y-2=3/8(x-7/2)
8y-16=3x-21/2
16y-32=6x-21
16y-6x=-21+32
16y-6x=11
