Answer:
g(x) has a greater average rate of change
Step-by-step explanation:
From the given information, the table is:
x | g(x)
-1 7
0 5
1 7
2 13
From this table, we have g(0)=5 and g(2)=13
The average rate of change over [a,b] of g(x) is given by: [tex]\frac{g(b)-g(a)}{b-a}[/tex]
This implies that on the [0,2]. the average rate of change is:
[tex]\frac{g(2)-g(0)}{2-0}=\frac{13-5}{2}=\frac{7}{2}=3.5[/tex]
Also, we have that: f(0)=-4 and f(2)=-1.
This means that the average rate of change of f(x) on [0,2] is
[tex]\frac{f(2)-f(0)}{2-0}=\frac{-1--4}{2} =\frac{3}{2} =1.5[/tex]
Hence g(x) has a greater average rate of change on [0,2]
