Answer:
D
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + y² = z² , substitute values
4² + y² = ([tex]\sqrt{137}[/tex] )², that is
16 + y² = 137 ( subtract 16 from both sides )
y² = 121 ( take the square root of both sides )
y = [tex]\sqrt{121}[/tex] = 11 → D
