Answer:
Explanation:
There are several ways to solve this using different assumptions.
First you need to imagine an isosceles triangle formed by:
You can solve for x in several ways.
I will use the cosine rule:
[tex]c^2=a^2+b^2-2accos(\alpha)[/tex]
Where:
[tex]c=x\\\\a=234,000miles\\\\b=234,000miles\\\\\alpha=30seconds[/tex]
One second of degree equals 1/3600 degrees:
[tex]30seconds\times 1degree/3600seconds=1/120degrees[/tex]
Substitute in the equation and compute:
[tex]x^2=(234,000miles)^2+(234,000miles)^2-2(234,000miles)(234,000miles)\times cos(1/120\º)[/tex]
[tex]x=579.15mile\approx600miles[/tex]