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The length of a rectangle is 2 feet more than the width. If it’s perimeter is 40 feet, find the length and width

Respuesta :

ujalakhan18

Answer:

w=9 feet

l=11 feet

Step-by-step explanation:

Let the length of the rectangle be l and width be w

Condition 1:

l=2+w --------(I)

Condition 2:

2l+2w=40--------(2)

Putting eq (1) in (2)

2(2+w)+2w=40

4+2w+2w=40

4+4w=40

4w=40-4

4w=36

Dividing both sides by 4

w=9

Now

Putting w=9 in eq (1)

l=2+9

l=11

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