Respuesta :
Answer:
Explanation:
i) (18 X 336) air/h = 6048 air/h
Engine speed = 2500 rpm; Capacity of diesel = 800 ppm
∴ 2500/800 = 3.125 kg/pm
Mass flow rate = (3.125 X 6048) Kg/h/pm =18900 Kg/h/pm
ii) Mass flow rate = 32 X 4/1000 X 2500 = 320 Kg/h/pm
Answer:
mass flow rate of sulfur = 14.936*10^-3 kg/hr
mass flow rate of sulfurous acid = 38.23 * 10^-3 kg/hr
Explanation:
Please see attached images for detailed explanation.
Feel free to ask anything if it seems confusing. Thank you.


