A ball is thrown straight up with an initial speed of 36 m/s . Part A How much time does it take for the ball to reach the top of its trajectory?

Respuesta :

Answer:3.67 s

Explanation:

Given

Ball is thrown with an initial velocity of [tex]u=36\ m/s[/tex]

As the ball moves upward it experience a declaration due to gravity which will slow down the ball

using

[tex]v=u+at[/tex]

where v=final velocity

u=initial velocity

a=acceleration

t=time

Here [tex]v=0[/tex]

[tex]0=36-9.8\times t[/tex]

[tex]t=\frac{36}{9.8}[/tex]

[tex]t=3.67\ s[/tex]