Answer:
P(X=8)=11.2599 %
Step-by-step explanation:
According to the Poisson Model:
P=[tex]\frac{e^{-\lambda}\lambda^{x}}{x!}[/tex]
where:
λ is the average of cars sold
x is the number of cars sold tomorrow
P is the probability of cars sold tomorrow
In our case:
Given data:
λ=10 cars
x=8 cars
Required:
The probability that the dealer sells 8 cars tomorrow=?
Solution:
[tex]P=\frac{e^{-\lambda}\lambda^{x}}{x!}\\ P=\frac{e^{-10}10^{8}}{8!}\\P=0.112599\\P=11.2599\%[/tex]
P(X=8)=11.2599 %
