Answer:
The number of miles between the two airports is 11,664,000
Step-by-step explanation:
Distance (d) = Average speed (A) × time (t)
Let the actual time the airport would have arrived be y
When A = 540 mph = 540×60 = 32,400 mpm, t = (y+8) min
d = 32,400(y+8) -------(1)
When A = 480 mph = 480×60 = 28,800 mpm, t = (y+53) min
d = 28,800(y+53) -------(2)
Equating both equations
32,400(y+8) = 28,800(y+53)
32,400y+259,200 = 28,800y+1,526,400
32,400y - 28,800y = 1,526,400 - 259,200
3,600y = 1,267,200
y = 1,267,200/3600 = 352 min
d = 32,400(y+8) = 32,400(352+8) = 32,400×360 = 11,664,000 miles