Answer:[tex]\theta =28.42^{\circ}[/tex]
Explanation:
Given
Area of surface [tex]A=7\ m^2[/tex]
Electric Field strength [tex]E=6\times 10^5\ N/C[/tex]
Flux through Surface [tex]\phi =2\times 10^6\ N-m^2/C[/tex]
Surface is Oriented with Electric field at an angle [tex]\theta [/tex]
so Angle between Area vector and Electric Field is [tex]\angle =90-\theta [/tex]
And flux is given by
[tex]\phi =\vec{E}\cdot \vec{A}[/tex]
[tex]\phi =E\cdot A\cos (90-\theta )[/tex]
[tex]2\times 10^6=6\times 10^5\times 7\times \cos (90-\theta )[/tex]
[tex]\sin \theta =0.476[/tex]
thus [tex]\theta =28.42^{\circ}[/tex]
