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A boat crosses a river of width 244 m in which the current has a uniform speed of 1.99 m/s. The pilot maintains a bearing (i.e., the direction in which the boat points) perpendicular to the river and a throttle setting to give a constant speed of 1.68 m/s relative to the water. How far downstream from the initial position is the boat when it reaches the opposite shore

Respuesta :

Answer:289.02\ m

Explanation:

Given

width of river [tex]d=244\ m[/tex]

velocity of current [tex]v_1=1.99\ m/s[/tex]

Velocity of boat w.r.t to current [tex]v_{21}=1.68\ m/s[/tex] perpendicular to current

therefore Perpendicular component of velocity will help boat to cover the width of river in [tex]t_1[/tex] time which is given by

[tex]t_1=\frac{244}{v_{21}}[/tex]

[tex]t_1=\frac{244}{1.68}=145.23\ s[/tex]

In this time current will drift the boat a distance of

[tex]x=v_1\times t_1[/tex]

[tex]x=1.99\times 145.23[/tex]

[tex]x=289.02\ m[/tex]  

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