Answer:
Width of the blueprint should be 20.89 ft.
Step-by-step explanation:
The given question is incomplete without an attachment. Here is the attachment.
In the figure attached, we have to find the missing dimension from the blueprint.
Since corresponding sides of the original court and it's blueprint will be in the same ratio.
Therefore, [tex]\frac{50}{x}=\frac{90}{37.6}[/tex]
x = [tex]\frac{5 \times 37.6}{9}[/tex]
x = 20.89 ft
Therefore, width of the blueprint is 20.89 ft.
