Answer:
d=4inches
Or d=10 inches
Step-by-step explanation:
Let d = depth of gutters
Let 28 - d be width of gutters
Cross sectional area of gutter = d(28-2d)
66 = d(28-2d)
66= 28d -2d^2
2d^2 - 28d +66=0
Dividing by 2 gives
d^2 - 14d +33
Using Almighty formular
d = -(-14) +- sqrt (-(-14)-(4×1×33)/2
d = 14+-sqrt(196-132)/2
d =14+-sqrt(64)/2
d= 14+- (8/2)
d=14+-4
d=14+4=18 or
d= 14-4=10