Answer: g = 6.65 m/s²
Explanation: The frequency of a simple pendulum is given by the formulae below
f = 1/2π *(√g/l)
Where f = frequency = number of oscillation /time =17/35.66 = 0.477Hz
g = acceleration due gravity in another planet
l = length of simple pendulum = 0.74m
0.477 = 1/2π * (√g/0.74)
0.477 = 1/2 * 3.142 * (√g/0.74)
0.477 = 1/ 6.284 * (√g/0.74)
0.477 = 0.1591 * (√g/0.74)
0.477/0.1591 = (√g/0.74)
2.998 = (√g/0.74)
By taking the square of both sides
8.988 = g/ 0.74
g = 6.65 m/s²
