Answer:
Explanation:
Given
Electric Field Strength [tex]E=3\times 10^6\ N/C[/tex]
When a charged particle enters the Electric field it Experience a force in the direction of electric field (for positive charge and vice-versa for negative charge)
charge on Electron [tex]q=1.6\times 10^{-19}\ C[/tex]
mass of electron [tex]m=9.1\times 10^{-31}\ kg[/tex]
Force [tex]F=q\times E[/tex]
[tex]F=1.6\times 10^{-19}\times 3\times 10^6[/tex]
[tex]F=4.8\times 10^{-13}\ N[/tex]
acceleration of electron [tex]a=\frac{F}{m}[/tex]
[tex]a=\frac{4.8\times 10^{-13}}{9.1\times 10^{-31}}[/tex]
[tex]a=0.527\times 10^{18}\ m/s^2[/tex]
