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Find conditions on k that will make the following system of equations have a unique solution. To enter your answer, first select whether k should be equal or not equal to specific values, then enter a value or a list of values separated by commas.

Then give a formula in terms of k for the solution to the system, when it exists. Be sure to include parentheses where necessary, e.g. to distinguish 1/(2k) from 1/2k.

3kx+3y = 4
3x+3ky = 1

The system has a unique solution when k (equal or not equal) to ???

The unique solution is x =__________

y =__________

Respuesta :

Kazeemsodikisola

Answer:

K should not be equal to 1 or -1

Step-by-step explanation:

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ashishdwivedilVT

The system consists unique solution when k is not equal to 1 or -1.

When a system of linear equations has a unique solution?

System of linear equations a₁x+b₁y+c₁=0  and a₂x+b₂y+c₂=0 will have a unique solution if,

[tex]\frac{a_{1} }{a_2} \neq \frac{b_1}{b_2}[/tex]

Given equations are:

3kx+3y = 4

3x+3ky = 1

For a unique solution,

[tex]\frac{3k}{3} \neq \frac{3}{3k}[/tex]

[tex]9k^2\neq 9\\\\k^2\neq 1\\\\k\neq 1\\k\neq -1[/tex]

Therefore, The system consists unique solution when k is not equal to 1 or -1.

To get more about the system of linear equations visit:

brainly.com/question/41264352

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