Respuesta :
Answer:
Explanation:
Mol weight of Cu(NO 3) 2 ( trihydrate form )
= 241.6 g
22.6 g of Cu(NO 3) 2
= 22.6 / 241.6
= 1 / 10 mole ( approx )
It will ionise in water as follows
Cu(NO 3) 2 ⇄ Cu ⁺² + 2 NO₃⁻¹
Total ions per molecule = 3 , because at this dilution molecule will be fully ionised.
Total ions per 1 /10 moles = 3 / 10 moles
= .3 moles.
Answer: 0.360 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{22.6g}{187.56g/mol}=0.120moles[/tex]
[tex]Cu(NO_3)_2(aq)\rightarrow Cu^{2+}(aq)+2NO_3^-(aq)[/tex]
1 mole of [tex]Cu(NO_3)_2[/tex] gives = 3 moles of ions
0.120 moles of [tex]Cu(NO_3)_2[/tex] give= [tex]\frac{3}{1}\times 0.120=0.360[/tex] moles of ions.
Thus 0.360 moles of ions are present in an ideal solution that is produced by dissolving 22.6 g of [tex]Cu(NO_3)_2[/tex] in 323 g of water
