Answer:
36.66
Explanation:
The mean of a discrete uniform distribution is the average of the boundaries:
μ=[tex]\frac{b+a}{2}[/tex]
The variance of a discrete uniform distribution is the difference of the boundaries decreased by 1 and squared, decrease by 1 and divided by
σ^2=[tex]\frac{(b-a+1)^2-1}{12}[/tex]
a)
Given:
a = 620 nm
b = 640 nm
Use the formulas to determine the mean and variance:
μ=[tex]\frac{620+640}{2}=630\\[/tex]
σ^2=[tex]\frac{(b-a+1)^2-1}{12}[/tex]
=(640-620+1)^2-1/12
=36.66
