Respuesta :

Eduard22sly

Answer: option A. 23g Na

Explanation:

To know which of the options are correct, let's solve each of the options

A. Mass of Na = 23g

MM of Na = 23g/mol.

n = Mass /Molar Mass

n = 23/23 = 1mole

B. Mass of carbon = 24g

MM of carbon = 12g/mol

n = Mass /Molar Mass

n = 24/12 = 2mole

C. Mass of Kr = 42g

MM of Kr = 84g/mol

n = Mass /Molar Mass

n = 42/84 = 0.5mole

D. Mass of K = 78g

MM of K = 39g/mol

n = Mass /Molar Mass

n = 78/39 = 2mole.

From the above illustration, only 23g of Na contains a mole of the atom

Lanuel

Sodium (Na) is the sample that contains a mole of atoms.

Given the following data:

  • Mass of Na = 23 g
  • Mass of C = 24 g
  • Mass of Kr = 42 g
  • Mass of K = 78 g

Scientific data:

  • Molar mass of Na = 23 g/mol.
  • Molar mass of C = 12 g/mol.
  • Molar mass of Kr = 83.798 g/mol.
  • Molar mass of K = 39.098 g/mol.

To determine the sample contains a mole of atoms:

[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{23}{23}[/tex]

Number of moles = 1.0 moles

Therefore, sodium (Na) is the sample that contains a mole of atoms.

Read more on number of moles here: https://brainly.com/question/3173452

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