A certain metal has a resistivity of 1.68 × 10-8 Ω ∙ m. You have a long spool of wire made from this metal. If this wire has a diameter of 0.15 mm, how long should you cut a segment so its resistance will be 15 Ω?

Respuesta :

Answer:

15.78 m

Explanation:

Length = resistance×area/resistivity

Resistance = 15 ohms

Area = πd^2/4 = 3.142×(0.15/1000)^2/4 = 1.767375×10^-8 m^2

Resistivity = 1.68 ohm-meter

Length = 15×1.767375×10^-8/1.68×10^-8 = 15.78 m

For a wire that has a resistivity of 1.68 × 10-8 Ω ∙ m, diameter of 0.15mm, and resistance of 15Ω, the length is 1.63 m

The resistivity of the metal, [tex]\rho = 1.68 \times 10^{-8}[/tex]Ω ∙ m

The diameter of the wire, d = 0.15 mm

Convert the diameter to meter

[tex]d=0.15 \times 10^{-3}m[/tex]

Calculate the area of the wire

[tex]A=\frac{\pi d^2}{4} \\\\A=\frac{3.142 \times (0.15 \times 10^{-3})^2}{4} \\\\A = 1.77 \times 10^{-8}m^2[/tex]

Resistance, R = 15 Ω

The resistivity of a wire is calculated using the formula:

[tex]\rho =\frac{RA}{l}[/tex]

Solve for the length

[tex]l=\frac{RA}{\rho} \\\\l=\frac{15 \times 1.77 \times 10^{-8}}{1.68 \times 10^{-8}} \\\\l=1.63 m[/tex]

For a wire that has a resistivity of 1.68 × 10-8 Ω ∙ m, diameter of 0.15mm, and resistance of 15Ω, the length is 1.63 m

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