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In simplified​ form, the period of vibration P for a pendulum varies directly as the square root of its length L. If P is 1.5 sec when L is 36 ​in, what is the period when the length is 25 ​in?

Respuesta :

Answer:

1.25 s      

Explanation:

Given: [tex]P \propto \sqrt L[/tex]

P = 1.5 s

L = 36 in

L' = 25 in

P' = ?

[tex]\frac{P'}{P}=\frac{\sqrt L'}{\sqrt L}\\P'=\frac{\sqrt L'}{\sqrt L}\times P\\P'= \frac{\sqrt {25 in}}{\sqrt {3.6in}}\times 1.5s\\P'=1.25s[/tex]

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