A 50 m vertical tower is braced with a 7 AM long cable secured at the top of the tower. What is the angle of depression from the top of the tower to the point on the ground where the cable is tied.

Respuesta :

Answer:

[tex]45.58^{\circ}[/tex]        

Step-by-step explanation:

Please find the attachment.

We have been given that a 50 m vertical tower is braced with a 70 m long cable secured at the top of the tower.

We can see that the cable and tower form a right triangle with respect to ground.

To solve for x, we will use sine as tangent relates opposite side of a right triangle to its hypotenuse.

[tex]\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}[/tex]      

[tex]\text{sin}(x)=\frac{50}{70}[/tex]

[tex]x=\text{sin}^{-1}(\frac{5}{7})[/tex]

[tex]x=45.58469^{\circ}[/tex]

[tex]x\approx 45.58^{\circ}[/tex]

Therefore, the angle of depression, from the top of the tower to point on the ground where the cable is tied, would be 45.58 degrees.

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