Answer:
The approximate discharge of the water as it flows down the waterfall is 1920 [tex]\frac{ft^{3} }{second}[/tex]
Explanation:
Calculate cross-sectional area:
Cross-sectional area = 16 ft x 8 ft = 128 [tex]ft^{2}[/tex]
Velocity = 15 [tex]\frac{ft}{second}[/tex]
Calculate discharge in feet per second:
Discharge = 128 [tex]ft^{2}[/tex] x 15 [tex]\frac{ft}{s}[/tex] = 1920 [tex]\frac{ft^{3} }{s}[/tex]
