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The following is a string of ASCII characters whose bit patterns have been converted into hexadecimal for compactness: 73 F4 E5 76 E5 4A EF 62 73.

Of the eight bits in each pair of digits, the leftmost is a parity bit. The remaining bits are the ASCII code.

(a) Convert the string to bit form and decode the ASCII.

(b) Determine the parity used: odd or even?

Respuesta :

mahamnasir

Answer:

a) Converting each string to bit form:

73:

The string is 7 and 3

7 in bit form is : 111

3 in bit form is: 11

So

73: 0_111_0011

Similarly

F4:

F is 15 and its bit form is: 1111

4 in bit form: 100

So

F4:  1_111_0100

E5:

E is 14 and its bit form is: 1110

5 in bit form: 101

So

E5:  1_110_0101

76:

7 in bit form: 111

6 in bit form: 110

So

76:  0_111_0110

E5:

E is 14 and its bit form is: 1110

5 in bit form: 101

So

E5:  1_110_0101

4A:

4 in bit form: 100

A is 10

A in bit form: 1010

So

4A:  0_100_1010

EF:

E in bit form is: 1110

F in bit form is: 1111

So

EF: 1_110_1111

62:

6 in bit form: 110

2 in bit form: 10

So

62:  0_110_0010

73:

The string is 7 and 3

7 in bit form is : 111

3 in bit form is: 11

So

73: 0_111_0011

for 0_1110011: the decimal is: 115 which is equal to s

for 1_1110100:  the decimal is: 116 which is equal to t

for 1_1100101:  the decimal is: 101 which is equal to e

for 0_1110110: the decimal is:  118 which is equal to v

for 1_1100101:  the decimal is: 101 which is equal to e

for 0_1001010: the decimal is:  74 which is equal to j

for 1_1101111: the decimal is: 111 which is equal to o

for 0_1100010:  the decimal is: 98 which is equal to b

for 0_1110011: the decimal is:  115 which is equal to s

So the decoded character is:  stevejobs

b) The parity used is odd.

for 0_1110011:  There are 5 number of 1s and parity is 0 so the parity is odd.

for 1_1110100: There are 4 number of 1s and parity is 1 so the parity is odd.

So here we are counting the number of 1s and then checking if the parity is even or odd.

Similarly

for 1_1100101:  parity is odd

for 0_1110110: parity is odd

for 1_1100101:  parity is odd

for 0_1001010: parity is odd

for 1_1101111: parity is odd

for 0_1100010: parity is odd

for 0_1110011: parity is odd

Hence the parity used is odd.

lhmarianateixeira

In this exercise we have to use the knowledge of converting string to bit and thus we will find that:

A)

  • 73: 0_111_0011
  • F4:  1_111_0100
  • E5:  1_110_0101
  • 76:  0_111_0110
  • E5:  1_110_0101
  • 4A:  0_100_1010
  • EF: 1_110_1111
  • 62:  0_110_0010
  • 73: 0_111_0011

B)

  • for 1_1100101:  parity is odd
  • for 0_1110110: parity is odd
  • for 1_1100101:  parity is odd
  • for 0_1001010: parity is odd
  • for 1_1101111: parity is odd
  • for 0_1100010: parity is odd
  • for 0_1110011: parity is odd

How to convert string to bit?

Converting string to binary and vice versa involves the process of encoding and decoding:

  • Encoding is the process of transforming a set of Unicode characters into a sequence of bytes.
  • Decoding is the process of transforming a sequence of encoded bytes into a set of Unicode characters.

a) Converting each string to bit form:

  • 73: The string is 7 and 3
  • 7 in bit form is : 111
  • 3 in bit form is: 11
  • F4:F is 15 and its bit form is: 1111
  • 4 in bit form: 100
  • E5:E is 14 and its bit form is: 1110
  • 5 in bit form: 101
  • 76:7 in bit form: 111
  • 6 in bit form: 110

  • E5:E is 14 and its bit form is: 1110
  • 5 in bit form: 101

  • 4A:4 in bit form: 100
  • A is 10
  • A in bit form: 1010
  • EF:E in bit form is: 1110
  • F in bit form is: 1111
  • 62:6 in bit form: 110
  • 2 in bit form: 10

  • 73:The string is 7 and 3
  • 7 in bit form is : 111
  • 3 in bit form is: 11

b)Converting each bit to decimal  form:

  • for 0_1110011: the decimal is: 115 which is equal to s
  • for 1_1110100:  the decimal is: 116 which is equal to t
  • for 1_1100101:  the decimal is: 101 which is equal to e
  • for 0_1110110: the decimal is:  118 which is equal to v
  • for 1_1100101:  the decimal is: 101 which is equal to e
  • for 0_1001010: the decimal is:  74 which is equal to j
  • for 1_1101111: the decimal is: 111 which is equal to o
  • for 0_1100010:  the decimal is: 98 which is equal to b
  • for 0_1110011: the decimal is:  115 which is equal to s

So the decoded character is:  steve jobs

for 0_1110011:  There are 5 number of 1s and parity is 0 so the parity is odd.

for 1_1110100: There are 4 number of 1s and parity is 1 so the parity is odd.

So here we are counting the number of 1s and then checking if the parity is even or odd.

See more about bits at brainly.com/question/2545808

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