Answer:
a
The impulse response is [tex]h(t) = 3e^{-2t}u(t)[/tex]
b
The step response of the system is = [tex]y(t)=\frac{3}{2} [1-e^{-2t}]u(t)[/tex]
c
The response signal is
Output = [tex]\frac{3}{2} [1-e^{-2(t-\frac{1}{2} )}]u(t-\frac{1}{2} ) -\frac{3}{2} [1-e^{-2(t-\frac{3}{2} )}]u(t-\frac{3}{2} )[/tex]
Step-by-step explanation:
The explanation is shown on the first and second uploaded image
