Respuesta :

Padoru

Hello there! We are given the following equation and want to simplify it:

[tex](x+y+2)(y+1)[/tex]

First, let's use the Distributive Property:

  • [tex](a+b)(c)=ac+bc[/tex]

For this step, we are going to let:

  • [tex]a=y[/tex]
  • [tex]b=1[/tex]
  • [tex]c=(x+y+2)[/tex]

After applying this version of the Distributive Property, we are given the equation:

[tex](y)(x+y+2)+(1)(x+y+2)[/tex]

We're going to use the distributive party again, but a slightly different version that's almost the same as first:

  • [tex](a)(b+c+d)=ab+ac+ad[/tex]

Using this on both terms of the equation changes the equation to:

[tex](xy+y^2+2y)+(x+y+2)[/tex]

Now, we just remove the parenthesis and combine like terms

[tex]y^2+3y+xy+x+2[/tex]

This should be your answer. Let me know if you need any clarifications, thanks!

~ Padoru