Answer:
6.1%
Explanation:
Assuming pressure inside balloon remains constant during the temperature change.
Therefore, as per Charles' law at constant pressure,
[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
[tex]T_2=39\°\ C=39+273=312\ K[/tex]
[tex]T_1=59°\ C=273+59=332\ K[/tex]
[tex]V_2=V_1\times \frac{T_2}{T_1} \\=V_1\times\frac{312}{332}\\=0.939V_1[/tex]
Percentage change in volume
[tex]\%\ change\ in\ volume=\frac{V_1-0.939V_1}{V_1} \times 100\\=6.1\%[/tex]
Change in volume of the balloon is 6.1%
