Answer:
161.6, 160.16,160.016
Explanation:
Given Data:
t = 5
difference quotients ; h= 0.1, h= 0.01, h=0.001
According to difference quotient
V = [tex]\frac{f(x+h)-f(x)}{h}[/tex]
where x = 5 = t and f=16t²
we get,
v = [16(5+h)² - 16(5)²]/h
v =16h + 160
Now,
At h=0.1; we get v= 161.6
At h=0.01; we get v= 160.16
At h=0.001; we get v= 160.016