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Towers A and B are located 10 miles apart. A ranger spots a fire at a 42-degree angle from tower A. Another fire ranger spots the same fire at a 64-degree angle from tower B. To the nearest tenth of a mile, how far from tower B is the fire? 7.0 mi 7.4 mi 9.4 mi 13.4 mi

Respuesta :

Using the law of sines, the distance between tower B and the fire is: 7 miles.

What is the Law of Sines?

Law of Sines is given as:

sin A/a = sin B/b = sin C/c

Let the position of the fire be represented as C.

Thus:

m∠C = 180 - 42 - 64 = 74°

c = 10 miles

m∠A = 42°

Distance between tower B and the fire = a

Therefore:

sin 42/a = sin 74/10

a = (sin 42 × 10)/sin 74

a = 7 miles

Therefore, using the law of sines, the distance between tower B and the fire is: 7 miles.

Learn more about law of sines on:

https://brainly.com/question/4372174

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