Answer:
Electric field at the center will be zero
Explanation:
Data provided in the question:
Radius of the solid sphere, R = 37 cm
Total positive charge, q = 14.6 μC
Now,
By Gauss law , we know that
E(4πr²) = Qε₀
E is the electric field
Q = [tex]\rho (\frac{4}{3}\pi r^3)[/tex]
Thus,
E(4πr²) = [tex]\frac{\rho (\frac{4}{3}\pi r^3)}{\epsilon_0}[/tex]
or
E = [tex]\frac{\rho r}{3\epsilon_0}[/tex]
here,
r is the distance of the point of observation from the center of the sphere,
at the center r = 0
Hence,
Electric field at the center will be zero
