Answer:
In this question we are given a composition of rigid motions. Thus whatever the area moves toward or across, is it is a rigid motion the area and angles will be preserved thus, the area of [tex]ABCD[/tex] is equal to the area of A''B''C''D''.
Step-by-step explanation:
As we are given some rigid motions, first we reflect [tex]ABCD[/tex] across [tex]x=3[/tex], which is said to be a rigid motion so, the length and angles of
Thus,
[tex]A''B''C''D''=(T(1,2)oR_{k} )*(ABCD)[/tex]
