Suppose that a disease is inherited via a sexlinked mode of inheritance so that a male offspring has a 50% chance of inheriting the disease, but a female offspring has no chance of inheriting the disease. Further suppose that 51.3% of births are male. What is the probability that a randomly chosen child will be affected by the disease?

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joaobezerra joaobezerra · Answer 1 · 2020-02-14T18:39:36+01:00

Answer:

There is a 25.65% probability that a randomly chosen child will be affected by the disease.

Step-by-step explanation:

We have these following probabilities:

A 51.3% probability that a child is born male.

A 100-51.3 = 48.7% probability that a child is born female.

A male child has a 50% probability of inheriting the disease.

A female hild has a 0% probability of inheriting the disease.

What is the probability that a randomly chosen child will be affected by the disease?

This is the sum of male who inherits, and female who inherits.

So

[tex]P = 0.513*0.5 + 0.487*0 = 0.2565[/tex]

There is a 25.65% probability that a randomly chosen child will be affected by the disease.