cjeastman5470 cjeastman5470

14-02-2020
Physics

contestada

Light of wavelength 480 nm illuminates a double slit, and the interference pattern is observed on a screen. At the position of the m = 4 bright fringe, how much farther is it to the more distant slit than to the nearer slit?

Respuesta :

madihasaadmamoon madihasaadmamoon

17-02-2020

Answer:

BC =980nm

Explanation:

Given wavelength =490nm

m=2

Required to find (OB - OC) = BC (more distant slit - nearest slit ) = dsin theta

We have dsin theta = m*wavelength

or BC = m* wavelength = 2*490nm

= 980nm = 98.000A

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