The​ architect's side view drawing of a​ saltbox-style house shows a post that supports the roof ridge. The support post is 15 ft tall. The distance from the front of the house to the support post is less than the distance from the post to the back of the house. How far from the front of the house is the support post​ positioned?

Respuesta :

Answer:

21 ft

Step-by-step explanation:

We are given that the support post is 10 ft tall.

Let x represents the distance between the support post and the front of the house, that means that 25-x will be the distance from back.

By Geometric Mean Theorem, the length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

So, by the previous Theorem, we get:

[tex]\frac{25}{10} =\frac{10}{x} \\25x=100\\x=100:25\\x=4[/tex]

We got that the distance between the support post and the front of the house is 4 ft, while the distance between the support post and the back of the house is [tex]25-4=21[/tex] ft.    

The distance from the front of the house to the support post​ is 12feet

Given the following parameter:

  • Height of the support post = 15ft

Let x represents the distance between the support post and the front of the house,

  • Distance from the front = 25 - x

According to the altitude theorem:

26/15 = 15/x

225 = 26x

x ≈ 14 feet

Get the distance from the front of the house to the support post​.

Required distance = 26 - 14

Required distance 12 feet

Hence the distance from the front of the house to the support post​ is 12feet

Learn more on altitude theorem here: https://brainly.com/question/11236033

Ver imagen abidemiokin