Answer:
E. I, II, and III.
Explanation:
I. C6H5NH2 + H2O --> C6H5NH3^+ + OH-
C6H5NH2 is a weak base means it is a good proton donor (strong conjugate acid).
II. Any aqueous acid with a pKa value of less than 0 is almost completely deprotonated and is considered a strong acid.
pka1 = - log[1 x 10^-3]
= 2
pka1 = - log[1 x 10^-4]
= 3
pka1 is a stronger acid.
III. A strong acid will be completely dissociated at equilibrium.