Answer: Molar heat capacity at constant volume of [tex]N_2[/tex] is 64.9 J/Kmol
Explanation:
[tex]C_p-C_v =nR[/tex]
where
[tex]C_p[/tex] = heat capacity at constant pressure
[tex]C_v[/tex] = heat capacity at constant volume
n = number of moles = 3.0
R= gas constant = 8.314 J/Kmol
[tex]Cp =\frac{q}{ΔT}[/tex]
q = heat absorbed
[tex\\Delta T[/tex] = change in temperature = 2.55 K
[tex]Cp =\frac{229J}{2.55K}=89.8J/K[/tex]
Putting in the values:
[tex]89.8_C_v=3.0\times 8.314[/tex]
[tex]C_v=89.8-24.9=64.9J/Kmol[/tex]
Thus molar heat capacity at constant volume of [tex]N_2[/tex] is 64.9 J/Kmol