Respuesta :
Explanation:
Equation of the reaction:
H2X(aq) + 2NaOH(aq) --> Na2X + 2H2O
Mass of acid = 0.178 g
Number of moles = molar concentration * volume
= 0.095 * 25.20 mL⋅1 L/1000 mL
= 0.00239 mol
From the equation of reaction,
2 moles of NaOH neutralises in 1 mole of H2X.
Therefore,
0.00239 mole of NaOH, number of koles of H2X = 2 * 0.00239 mol
= 0.0012 mole.
Molar mass = mass/number of moles
= 0.178/0.0012
= 148.7 g/mol.
The formula weight (molar mass) of the acid is 148.7g/mol.
Given chemical equation:
[tex]H_2X(aq) + 2NaOH(aq) --> Na_2X + 2H_2O[/tex]
Given:
Mass of acid = 0.178 g
Molarity:
- Molar concentration or molarity is defined as the ratio of number of moles over volume.
- [tex]M=\frac{n}{V}[/tex]
[tex]\text{Number of moles} = \text{molar concentration} * \text{volume}\\\\\text{Number of moles} = 0.095 * 25.20 mL*1 L/1000 mL\\\\\text{Number of moles} = 0.00239 mol[/tex]
From the equation of reaction,
2 moles of NaOH neutralizes in 1 mole of [tex]H_2X[/tex].
Therefore,
0.00239 mole of NaOH, number of moles of [tex]H_2X[/tex]
[tex]=2 * 0.00239 mol\\\\= 0.0012 mol[/tex]
Number of moles:
It is given by:
[tex]\text{Number of moles} =\frac{\text{Given mass}}{\text{Molar mass}} \\\\ \text{Molar mass}=\frac{\text{Given mass}}{\text{Number of moles}}\\\\ \text{Molar mass}= \frac{0.178}{0.0012}\\\\\text{Molar mass}= 148.7 g/mol[/tex]
Thus, the formula weight (molar mass) of the acid is 148.7g/mol.
Find more information about Molar mass here:
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