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A hanging block oscillating on the end of a spring passes through equilibrium at a speed of 2.0 m/s. It returns to equilibrium 0.75 s later. Calculate the total distance that it traveled between these two moments in its vibration. (Hint: How is the time related to the period? How is the distance traveled related to the amplitude?)

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Onoriodefelix

Answer:

1.5

Explanation:

From the question ,

velocity v= 2.0m/s

Time t = 0.75secs

Distance =?

Velocity = distance/ time

2.0 = d/0.75

Crossmultipy

d = 2.0 x 0.75

= 1.5m

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