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when heated, the temperature of a water sample increased from 15 degrees celsius to 39 degrees celsius. It absorbed 4300 joules of heat. What is the mass, in grams, of the sample?

Respuesta :

Mass of water: 43 g

Explanation:

When a substance is heated, the temperature of the susbtance increases according to the equation:

[tex]Q=mC\Delta T[/tex]

where

Q is the amount of heat supplied to the substance

m is the mass of the substance

C is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the increase in temperature

In this problem, we have:

Q = 4300 J is the heat absorbed by the water

C = 4200 J/gC is the specific heat capacity of water

[tex]\Delta T = 39-15 = 24^{\circ}C[/tex] is the increase in temperature

By re-arranging the equation, we can find the mass:

[tex]m=\frac{Q}{C \Delta T}=\frac{4300}{(4200)(24)}=0.043 kg = 43 g[/tex]

Learn more about specific heat:

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