Mass of water: 43 g
Explanation:
When a substance is heated, the temperature of the susbtance increases according to the equation:
[tex]Q=mC\Delta T[/tex]
where
Q is the amount of heat supplied to the substance
m is the mass of the substance
C is the specific heat capacity of the substance
[tex]\Delta T[/tex] is the increase in temperature
In this problem, we have:
Q = 4300 J is the heat absorbed by the water
C = 4200 J/gC is the specific heat capacity of water
[tex]\Delta T = 39-15 = 24^{\circ}C[/tex] is the increase in temperature
By re-arranging the equation, we can find the mass:
[tex]m=\frac{Q}{C \Delta T}=\frac{4300}{(4200)(24)}=0.043 kg = 43 g[/tex]
Learn more about specific heat:
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