Answer: the horizontal distance travelled is 2352 feet
Step-by-step explanation:
The altitude of the airplane, the horizontal distance that it travelled and the angle, θ formed with the ground combine to form a right angle triangle.
The horizontal distance that it travelled represents the adjacent side of the right angle triangle.
The altitude that it reached represents the opposite side of the right angle triangle. To determine the horizontal distance that it has travelled, h, we would apply the tangent trigonometric ratio which is expressed
Tan θ = opposite side/adjacent side
Therefore,
Tan 12 = 500/h
h = 500/Tan 12 = 500/0.2126
h = 2352 feet
The plane has covered 2352.32 feet of horizontal distance.
Given information:
An airplane climbs at an angle of 12 degrees with the ground.
The altitude reached by plane is 500 feet.
A right angles triangle will be formed by the initial position, final position, and the ground. See the attached image.
It is required to find the horizontal distance covered by the plane.
So, the value of horizontal distance covered by the plane will be calculated as,
[tex]tan \theta=\dfrac{h}{d}\\tan12^{\circ}=\dfrac{500}{d}\\d=2352.32\rm \; ft[/tex]
Therefore, the plane has covered 2352.32 feet of horizontal distance.
For more details, refer to the link:
https://brainly.com/question/2801100
