Answer:
Step-by-step explanation:
Both cylinders have same radius R and released from the same height.
If R rolls without slipping i.e. Pure rolling and S rolls on the smooth Plane.
Velocity possessed by both cylinder at bottom will be different because one is in pure rolling while other is not.
acceleration for pure rolling is given by
[tex]a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}[/tex]
where a=acceleration
[tex]\theta [/tex]=inclination of Plane
I=moment of inertia
for cylinder without rolling acceleration is given by
[tex]a=g\sin \theta [/tex]
Thus we can see that acceleration of S is more therefore S takes less time to reach bottom.