A certain shop repairs both audio and video components. Let A denote the event that the next component brought in for repair is an audio component, and let B be the event that the next component is a compact disc player (so the event B is contained in A). Suppose that P(A) 1?4 .6 and P(B) 1?4 .05. What is P(B | A)?

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Answer:

The correct answer is, P (B | A) = 0.0833.

Step-by-step explanation:

It is provided that:

A = the event that the next component brought in for repair is an audio component.

B = the event that the next component is a compact disc player

The event B is contained in A. This implies that P (B) = P (A and B) .

P (A) = 0.60 and P (B) = P (A and B) = 0.05.

According to the conditional probability rule:

[tex]P(X|Y)=\frac{P(X\cap Y)}{P(Y)}[/tex]

Determine the probability of the event (B | A) is:

[tex]P (B|A)=\frac{P(A\cap B)}{P(A)}=\frac{0.05}{0.60}= 0.0833[/tex]

Thus, the probability of event B given event A is 0.0833.