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A mass of 2.5 kg is connected to a horizontal spring whose stiffness is 6.1 N/m. When the spring is relaxed, x= 0. The spring is stretched so that the initial value of x= +0.19 m. The mass is released from rest at time t= 0. Remember that when the argument of a trigonometric function is in radians, on a calculator you have to switch the calculator to radians or convert the radians to degrees. Predict the position x when t= 1.41 s:

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Answer:

-0.132576156375 m

Explanation:

x = Displacement of spring = 0.19

k = Spring constant = 6.1 N/m

m = Mass = 2.5 kg

Angular frequency is given by

[tex]\omega=\sqrt{\dfrac{k}{m}}\\\Rightarrow \omega=\sqrt{\dfrac{6.1}{2.5}}\\\Rightarrow \omega=1.56204993518\ rad/s[/tex]

Displacement of spring is given by

[tex]x=0.19cos(\omega t)[/tex]

when t = 1.41 s

[tex]x=0.19cos(1.56204993518\times 1.5)\\\Rightarrow x=-0.132576156375\ m[/tex]

The position is -0.132576156375 m

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