Answer:
[tex]W = -4.95 \times 10^4\ J[/tex]
Explanation:
given,
In first case Volume remains constant.
Work done in the first case is zero.
In Second case Volume change
V₁ = 0.2 m³
V₂ = 0.11 m³
Pressure, P = 5.5 x 10⁵ Pa
Work done = Pressure x change in volume
W = P ΔV
[tex]W = P(V_2-V_1)[/tex]
[tex]W = 5.5\times10^5\times (0.11 - 0.2)[/tex]
[tex]W = -4.95 \times 10^4\ J[/tex]
Hence, Work done when volume changes is equal to [tex]W = -4.95 \times 10^4\ J[/tex]
