A projectile is released with an initial (vertical) velocity of 95 m/s. Use the formula v(t) = 95 − 9.8t for velocity to determine the distance traveled during the first 14 s. (Round your answer to two decimal places.)

Respuesta :

Answer:

[tex]s = 369.6\ m[/tex]

Explanation:

given,

v(t) = 95 − 9.8 t

time, t= 14 s

velocity is the change in distance of an object in the given interval of time.

[tex]\dfrac{ds}{dt}=95-9.8 t[/tex]

[tex]ds = (95 - 9.8 t)dt[/tex]

integrating both side

[tex]\int ds = \int (95-9.8 t)dt[/tex]

[tex]s = 95 t-9.8\dfrac{t^2}{2}[/tex]

now,

Distance traveled by the object in 14 s

t = 14

[tex]s = 95\times 14-9.8\dfrac{14^2}{2}[/tex]

[tex]s = 369.6\ m[/tex]

Distance traveled by the object is equal to 369.6 m