Respuesta :
Answer:
Step-by-step explanation:
As I said in my Question I already know the "only way" to calculate this limit,
limh→0eh−1h=1
"the only way" i mean : using this definition
limx→∞(1+1x)x=e
by substituting x=1/h you can rewrite it as
e=limh→0(1+h)1/h
then :
limh→0eh=limh→0((1+h)1/h)h=limh→0(1+h)
so you can easily prove it the limit equal to one
limh→0eh−1h=1
so we can say that : this limit is just redefine of the definition of the e number
