Respuesta :
Answer:
a) h = 1990 m, b) the height we can reach increases , c) h = 2,329 m
Explanation:
.a) For this fluid mechanics problem let's use the pressure ratio
P = P₀ + ρ g y
P-P₀ = ρ g y
Where rho is the fluid density where it is contained, P₀ is the atmospheric pressure.
It does not indicate that the maximum pressure change before exporting is
ΔP = 2.32 * (0.1 P₀)
Let's look for this pressure
ΔP = 2.32 0.1 1.01 10⁵
ΔP = 0.234 10⁵ Pa.
This is the maximum pressure difference, let's look for the height where we reach this value, the container has an internal pressure of 2.02 10 Pa, which we must subtract from the initial difference
ΔP = ΔP - 2.02 10⁰ = 0.234 10⁵5 - 2.02
ΔP = 23398 Pa
ΔP = ρ g h
h = ΔP /ρ g
h = 23398 /1.20 9.8
h = 1990 m
b) If air density decreases the height from 1,225 at sea level to 0.3629 to 11000m, the height we can reach increases
Density must be functioned with height
c) Now we introduce the contain in the ocean, the density of sea water is
ρ = 1025 kg / m³
h = 23398 / 1025 9.8
h = 2,329 m
Hydrostatic pressure acts when fluid is at rest. The maximum height above the ground is 1990 m up to that the container can be lifted before bursting.
From the hydrostatic pressure formula,
[tex]P = \rho gh[/tex]
Where,
[tex]P[/tex] - pressure = 23398 Pa
[tex]\rho[/tex] - density of th ewater = [tex]\bold {1.2 m^3}[/tex]
[tex]g[/tex] - gravitational acceleration = 9.8 m/s²
[tex]h[/tex] - height = ?
Put the values in the formula, calculate for [tex]h[/tex],
[tex]h = \dfrac { 23398 }{1.2 \times 9.8 }\\\\h = 1990 \rm \ m[/tex]
The maximum height above the ground is 1990 m up to that the container can be lifted before bursting.
To know more about hydrostatic pressure,
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