Answer:
t=0 Sugar = 0 Kg
t=1min Sugar=0.27 Kg
Step-by-step explanation:
Data
Tank = 2640 L (pure water)
Sol=0.09kg Sugar per liter
Vin = Vout = 3L/min
Sugar in the beginning = ?
if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water
, but if beginning is t= 1min then;
[tex]\frac{3L}{min}*\frac{0.09Kg}{L}=0.27kg/min[/tex]
