Answer:
[tex]F'=4F[/tex]
Explanation:
According to Coulomb's law, the magnitude of the force (F) between two objects with the same charge(+Q), separated a distance (d) apart, is defined as:
[tex]F=\frac{kQ^2}{d^2}[/tex]
Here k is the Coulomb constant. The charge on each object is doubled, that is [tex]Q'=2Q[/tex]:
[tex]F'=\frac{kQ'^2}{d^2}\\F'=\frac{k(2Q)^2}{d^2}\\F'=4\frac{kQ^2}{d^2}\\F'=4F[/tex]
